Import Question JSON

Current Question (ID: 12541)

Question:
In monocot leaf 1. Stomata is present on both surface of epidermis 2. Mesophyll is not differentiated into palisade and spongy parenchyma 3. There is no parenchyma 4. Both 1 and 2
Options:
  • 1. Stomata is present on both surface of epidermis
  • 2. Mesophyll is not differentiated into palisade and spongy parenchyma
  • 3. There is no parenchyma
  • 4. Both 1 and 2
Solution:
In monocot leaves, stomata are present on both surfaces of the epidermis, which is the outermost layer of the leaf. This is in contrast to dicot leaves, where stomata are typically found only on the lower surface of the leaf. Additionally, the mesophyll of monocot leaves is not differentiated into palisade and spongy parenchyma, unlike dicot leaves. Instead, the mesophyll is composed of elongated cells that are arranged parallel to the leaf surface. These cells contain chloroplasts and carry out photosynthesis. Option 3, "there is no parenchyma," is incorrect, as parenchyma cells are present in the mesophyll of monocot leaves, although they are not differentiated into palisade and spongy layers.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}