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Current Question (ID: 12552)

Question:

A tree can be killed by removing its bark, as this also removes the ________.

Options:

1. Phelloderm only
2. Phellem only
3. Primary xylem
4. Secondary phloem

Solution:

A tree can be killed by removing its bark, as this also removes the secondary phloem. The bark of a tree consists of several layers of tissues, including the outermost layer of dead cork cells called the phellem or cork. Below the cork layer, there is a layer of living cells called the phloem, which is responsible for transporting sugars and other organic molecules from the leaves to the rest of the plant. The phloem also provides some structural support to the tree. The removal of the bark, including the phloem, disrupts the flow of sugars and other nutrients, which can ultimately kill the tree. Phelloderm is a thin layer of parenchyma cells that is produced inwardly by the cork cambium or phellogen. It is not directly involved in the transport of nutrients, and its removal is not fatal to the tree. Primary xylem is the first-formed xylem tissue, which is located towards the center of the stem or root. It is not located in the bark, and its removal alone would not be fatal to the tree.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}