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Current Question (ID: 12620)

Question:

Who first explained that new cells are formed from pre-existing cells

Options:

1. Theodor Schwann
2. Rudolf Virchow
3. Matthias Schleiden
4. Robert Hooke

Solution:

Rudolf Virchow told that omnis cellula-e cellula. Rudolf Virchow, a German physician and pathologist, is credited with first proposing the concept that new cells are formed from pre-existing cells in 1855. This idea, known as the principle of biogenesis, contradicted the previous notion of spontaneous generation, which suggested that living organisms could arise from non-living matter. Matthias Schleiden and Theodore Schwann are also significant figures in the development of cell theory, but they did not specifically propose the concept of new cells arising from pre-existing cells. Matthias Schleiden was a botanist who, in 1838, proposed that plants are made up of cells. Theodore Schwann, a zoologist, expanded on Schleiden's work and proposed that animals are also made up of cells in 1839. Robert Hooke, an English scientist, is known for observing and describing cells for the first time in 1665, but he did not propose the concept of new cells arising from pre-existing cells.

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}