Import Question JSON

Current Question (ID: 12636)

Question:

Eukaryotic cells considered as more efficient than prokaryotic cells, due to -

Options:

1. compartmentalisation of cytoplasm
2. Infolding of membrane
3. Presence of cell wall
4. Aerobic respiration

Solution:

Eukaryotic cells are more complex than prokaryotic cells and have a number of specialized membrane-bound organelles, such as the nucleus, mitochondria, and endoplasmic reticulum, which compartmentalize different cellular functions. This allows for more efficient regulation of cellular processes and greater specialization of cell function. Prokaryotic cells lack membrane-bound organelles and have a simpler internal structure. The infolding of membranes in prokaryotic cells, such as the plasma membrane and the mesosome, allows for increased surface area for chemical reactions, but does not provide the same level of compartmentalization as eukaryotic cells. The presence of a cell wall is a feature of both prokaryotic and eukaryotic cells, but does not necessarily make one more efficient than the other. Aerobic respiration is a process by which cells produce energy from glucose using oxygen, and is a feature of both prokaryotic and eukaryotic cells.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}