Import Question JSON

Current Question (ID: 12642)

Question:
A common characteristic feature of plant sieve tube cells and most mammalian erythrocytes is
Options:
  • 1. absence of mitochondria
  • 2. presence of cell wall
  • 3. presence of haemoglobin
  • 4. absence of nucleus
Solution:
The common characteristic feature of plant sieve tube and mammalian erythrocyte the absence of nucleus. Sieve tubes are the component of phloem and do not contain nucleus. Similarly, erythrocytes in mammalian cell also do not possess nucleus. Erythrocytes are the RBCs which helps in gaseous exchange. Mitochondria is absent in sieve tube cells. Pigment haemoglobin is present mammalian erythrocytes but not in sieve tube cells. Cell wall is made of cellulose and present in all plant cells, and thus absent in erythrocytes.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}