Import Question JSON

Current Question (ID: 12646)

Question:

Find out the incorrect statement

Options:

1. Middle lamella is mainly made up of Ca-pectate
2. Cell wall is formed from inner side therefore secondary wall formed before primary wall
3. Middle lamella glues the different neighbouring cells together
4. Pits are present in secondary wall

Solution:

The cell wall is a rigid structure that surrounds the cell membrane of plant, fungal, and bacterial cells. It provides support and protection to the cell and helps maintain its shape. The cell wall is formed from the outside in, with the primary wall being formed first and the secondary wall being added later in some cells. Option 1 is a correct statement. The middle lamella is primarily composed of calcium pectate, which is a complex polysaccharide composed of pectin and calcium ions. Option 3 is a correct statement. The middle lamella acts as an adhesive that glues neighbouring cells together. Option 4 is a correct statement. Pits are present in the secondary wall of plant cells, and they are areas where the wall is thinner and more flexible to allow for movement and communication between cells.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}