Import Question JSON

Current Question (ID: 12678)

Question:

The Golgi complex participates in?

Options:

1. Fatty acid breakdown
2. Formation of secretory vesicles
3. Respiration in bacteria
4. Activation of amino acid

Solution:

The Golgi apparatus is an organelle present in most eukaryotic cells, except in mature sieve tubes of plants, mature RBCs of mammals, sperm cells of bryophytes and pteridophytes, etc. It is absent in prokaryotic cells. It is a membrane-bound cell organelle and is also called dictyosomes as Golgi apparatus is made up of unconnected units. There are four parts of Golgi complex i.e., cisternae, tubules, vesicles, Golgian vacuoles. (a) Cisternae- The Golgi cisternae are concentrically arranged near the nucleus with distinct convex cis or the forming face and concave trans or the maturing face. (b) Tubules- Small, flat, interconnecting structures arising from the periphery of cisternae due to fenestrations (small opening or pore). (c) Vesicles- Largely rounded sacs present at the edge of cisternae in clusters and are of two types- (i) Smooth vesicles- Smooth surfaced secretory vesicles that contain secretory granules. (ii) Coated vesicles- Rough-surfaced, spherical protuberances arising from the tubules of cisternae. (d) Golgian Vacuoles- Large, spherical vacuoles produced at maturing face. Some of them function as lysosomes. The important function of the Golgi apparatus is to process, package, and transport the materials for secretions and it is the important site of formation of glycoproteins and glycolipids.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}