Import Question JSON

Current Question (ID: 12690)

Question:

Non-membranous nucleoplasmic structures in the nucleus, are the sites for active synthesis of:

Options:

1. protein
2. mRNA
3. rRNA
4. tRNA

Solution:

Non-membranous nucleoplasmic structures in the nucleus are the site for active synthesis of rRNA. The non-membranous nucleoplasmic structures in the nucleus that are responsible for the active synthesis of rRNA are called nucleoli. The nucleoli are composed of proteins and nucleic acids and are involved in the assembly of ribosomes, which are responsible for protein synthesis in the cytoplasm. Specifically, the nucleoli are responsible for synthesizing the rRNA component of ribosomes, which combines with proteins to form the complete ribosome. Option 1 is incorrect because protein synthesis occurs in the cytoplasm, not in the nucleus. Option 2 is incorrect because mRNA is synthesized in the nucleus but not in the nucleoli; rather, it is synthesized in the nucleoplasm and then exported to the cytoplasm for translation into proteins. Option 4 is incorrect because tRNA is also synthesized in the nucleoplasm, not in the nucleoli.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}