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Current Question (ID: 12814)

Question:
The typical growth curve in plants is:
Options:
  • 1. sigmoid
  • 2. linear
  • 3. stair-steps shaped
  • 4. parabolic
Solution:
The growth of plants is not a continuous process but can be divided into several distinct phases. The typical growth curve of plants shows an initial lag phase, followed by an exponential or log phase, a stationary phase, and finally a decline phase. The shape of this curve is sigmoid or S-shaped. During the lag phase, the plant is preparing for growth, and there is little or no increase in size or weight. During the exponential or log phase, there is a rapid increase in size and weight as the plant reaches its maximum growth rate. In the stationary phase, the growth rate slows down, and the plant reaches its maximum size and weight. Finally, in the decline phase, the plant begins to lose weight and size due to senescence, disease, or other factors. This typical growth curve may vary depending on the species of plant, environmental conditions, and other factors, but the overall shape of the curve is generally sigmoid.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}