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Current Question (ID: 12822)

Question:

Internodal segments of tobacco stems, the callus is actually

Options:

1. An undifferentiated cell
2. A mass of differentiated cell
3. A mass of undifferentiated cell
4. A differentiated cell

Solution:

When an internodal segment of a tobacco stem is cultured in vitro, the cells at the cut ends of the segment start to divide and form a mass of cells called callus. The callus is a disorganized mass of undifferentiated cells that have the ability to develop into any type of plant cell. This property of callus cells is called totipotency. The callus can be used to produce new plants through a process called somatic embryogenesis, which involves inducing the callus cells to form embryos that develop into new plants. Callus can also be used to study plant growth and development, and to produce secondary metabolites such as alkaloids and terpenoids.

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}