Import Question JSON

Current Question (ID: 12936)

Question:

Which one of the following statements is not correct?

Options:

1. Offspring produced by asexual reproduction is called clone
2. Microscopic motile asexual reproductive structures are called zoospores
3. In potatoes, bananas, and ginger, the plantlets arise from the internodes present in the modified stem
4. Water hyacinth growing in standing water drains oxygen from water that leads to the death of fish

Solution:

Plantlets always arise from nodes of stem or modified stem. Potato, Banana and ginger plants arise from axillary buds present in the nodes. In nature, many organisms produce clones through asexual reproduction. Cloning is the process of producing genetically identical individuals of an organism either naturally or artificially. Special asexual reproductive structures are formed in these organisms. Zoospores are the most common structure among such asexual reproductive structures. The zoospore is usually a microscopic motile structure. Other common asexual reproductive structures are conidia (Penicillium), buds (Hydra) and gemmules. Water hyacinth (Eicchornia), the aquatic plan is one of the most invasive weeds found growing wherever there is standing water. It drains oxygen from the water, which leads to the death of fishes.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}