Import Question JSON

Current Question (ID: 13144)

Question:

Find out the correct option: (1) Among animals, insects, particularly bees are the dominant biotic pollinating agents (2) Often flowers of animal-pollinated plants are specially adapted for particular species of animals (3) In some species floral rewards like edible nectar, pollen grains, shelter for egg laying are given to pollinating animals (4) All the above are correct

Options:

1. Among animals, insects, particularly bees are the dominant biotic pollinating agents
2. Often flowers of animal-pollinated plants are specially adapted for particular species of animals
3. In some species floral rewards like edible nectar, pollen grains, shelter for egg laying are given to pollinating animals
4. All the above are correct

Solution:

Bees are the dominant biotic pollinating agents because of the secretion of nectar by flowers, which is collected by them as floral reward to make honey. Some flowers are specially adapted for particular species of animals like daisy and aster attracts bees. Nectar, pollen grains and shelter for egg laying (the moth deposits its eggs in the locule of the ovary and the flower, in turn, gets pollinated by the moth) are the usual floral rewards.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}