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Current Question (ID: 13253)

Question:
Which of the following is not entirely true fact? 1. Competition occurs when closely related species compete for the same resources that are limiting 2. Totally unrelated species could compete for the same resource 3. Resources need not be limiting for competition to occur. In interference competition, the feeding efficiency of one species might be reduced due to the interference and inhibitory presence of the other species, even if resources are abundant. 4. A complex interplay of interspecific interactions and environmental variability characterizes community structure
Options:
  • 1. Competition occurs when closely related species compete for the same resources that are limiting
  • 2. Totally unrelated species could compete for the same resource
  • 3. Resources need not be limiting for competition to occur. In interference competition, the feeding efficiency of one species might be reduced due to the interference and inhibitory presence of the other species, even if resources are abundant.
  • 4. A complex interplay of interspecific interactions and environmental variability characterizes community structure
Solution:
Competition is a process in which the fitness of one species (measured in terms of its 'r' the intrinsic rate of increase) is significantly lower in the presence of another species. This is because totally unrelated species could also compete for the same resource.

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}