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Current Question (ID: 13323)

Question:
The mass of living material at a tropic level at a particular time is called
Options:
  • 1. Gross primary productivity
  • 2. Standing state
  • 3. Net primary productivity
  • 4. Standing crop
Solution:
The rate of production of organic matter (chemical energy) as biomass that primary producers (via photosynthesis) created in a given duration of time is called Gross Primary Productivity (GPP). Net primary production is the rate at which all plants (producers) in an ecosystem produce net useful chemical energy, it is equal to the difference between the rate at which plants in an ecosystem produce useful chemical energy (GPP) and the rate at which they use some of that energy during respiration. NPP = GPP - respiration (by plants) Secondary productivity is the generation of biomass or organic matter by heterotrophic (consumers) in a system. Net productivity is the amount of energy trapped in organic matter during a specific interval at a given trophic level less than that lost by the respiration of the organisms at that level. PAGE 247, XII NCERT

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}