Import Question JSON

Current Question (ID: 13586)

Question:

Vertebrates and seastars may seen as different as two animal groups can be, yet they share 1. The same type of body symmetry as adults. 2. A high degree of cephalization. 3. Certain developmental pattern, including the type of coelom formation. 4. The presence of endoskeleton that include cranium

Options:

1. The same type of body symmetry as adults.
2. A high degree of cephalization.
3. Certain developmental pattern, including the type of coelom formation.
4. The presence of endoskeleton that include cranium

Solution:

Both vertebrates (phylum Chordata) and sea stars (phylum Echinodermata) share certain developmental patterns, including the type of coelom formation. Coelom refers to the body cavity found in many animals, and its formation during embryonic development follows similar patterns in both vertebrates and echinoderms. Option 1 is incorrect as vertebrates and echinoderms do not have the same type of body symmetry as adults. Vertebrates typically exhibit bilateral symmetry, while echinoderms, including sea stars, exhibit radial symmetry. Option 2 is incorrect as echinoderms, including sea stars, do not exhibit a high degree of cephalization. Cephalization refers to the concentration of sensory organs and nervous tissue in the head region, which is more pronounced in animals with bilateral symmetry, like vertebrates. Option 4 is incorrect as sea stars do not possess an endoskeleton that includes a cranium. Vertebrates, on the other hand, possess an endoskeleton that includes a cranium to protect the brain and other sensory organs.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}