Import Question JSON

Current Question (ID: 13601)

Question:

Select the correct statement about class-Aves

Options:

1. They are warm blooded (homoiothermous) animals and are able to maintain a constant body temperature
2. Respiration occurs through lungs and air sacs connected to lungs for supplement respiration
3. They are oviparous with separate sexes, internal fertilisation and direct development
4. All of the above

Solution:

All of the statements are correct in relation to class Aves, which includes birds. Birds are warm-blooded (homoiothermous) animals, meaning they are able to maintain a constant body temperature regardless of the external environment. This allows them to adapt to a wide range of habitats and climates. Birds have lungs for respiration, and they also possess specialized air sacs connected to their lungs that aid in respiration. These air sacs help in efficient gas exchange and allow for a continuous flow of fresh air through the lungs, which is important for their high metabolic rate and the demands of flight. Birds are oviparous, meaning they lay eggs, and they reproduce with separate sexes, internal fertilization, and direct development. Birds typically lay hard-shelled eggs that are incubated outside the body until they hatch.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}