Import Question JSON

Current Question (ID: 13705)

Question:

Assertion (A) Bidder canal is associated with the conduction of sperms of frog. Reason (R) These canals are the part of frog’s reproduction system and connect to the cloaca of frog.

Options:

1. Both Assertion and Reason are true and Reason is the correct explanation of Assertion
2. Both Assertion and Reason are true, but Reason is not the correct explanation of Assertion
3. Assertion is true, but Reason is false
4. Both Assertion and Reason are false

Solution:

In the male frog, there are 10-12 very fine tubules called Vasa efferentia connecting the testes of kidneys on each side. The vasa efferentia run transversely through the mesorchium (double fold of peritoneum) enter the kidneys and open into the Bidder's canal. The sperms produced by the testes are passed into Bidder's canal via vasa efferentia and then carried finally to the urinogenital duct. Duct arising from kidney in male frog is both a urinary duct and a sperm duct, hence it is called a urinogenital duct. Each urinogenital duct runs posteriorly and opens into the cloaca. The cloaca is a common chamber which receives fecal matter, urine and sperms.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}