Import Question JSON

Current Question (ID: 13747)

Question:

Which of the following provides structural and functional link between the individual cells in epithelial tissues?

Options:

1. Extracellular fluid which binds the various cells in the tissue together
2. Cell junctions
3. Connective tissue
4. Basement membrane

Solution:

Cell junctions are specialized structures present in the plasma membrane of adjacent cells in epithelial tissues that provide a mechanical and functional link between the individual cells. They play an important role in maintaining the integrity and barrier function of epithelial tissues. There are three main types of cell junctions: tight junctions, adherens junctions, and desmosomes. Tight junctions prevent the passage of molecules between adjacent cells, adherens junctions anchor adjacent cells together, and desmosomes provide strong mechanical attachments between cells. The extracellular matrix (ECM) and basement membrane also contribute to the structural support of epithelial tissues, but they are not directly involved in the link between individual cells. Connective tissue provides support and cushioning to epithelial tissues but does not provide a direct link between the individual cells.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}