Import Question JSON

Current Question (ID: 13754)

Question:

The excess of nutrients which are not used immediately are converted into fats and stored in

Options:

1. Areolar tissue
2. Adipose tissue
3. Dense regular connective tissue
4. Dense irregular connective tissue

Solution:

Adipose tissue is a specialized type of connective tissue that stores excess nutrients in the form of triglycerides, which are stored as fat droplets in adipocytes. When the body needs energy, these triglycerides can be broken down and used as fuel. Adipose tissue is found throughout the body, including under the skin, around organs, and within bone marrow. Areolar tissue is a loose connective tissue that provides support and flexibility to organs and connects them to each other. Dense regular connective tissue consists of tightly packed collagen fibers that provide strength and support to structures such as tendons and ligaments. Dense irregular connective tissue is similar to dense regular connective tissue, but with a more random arrangement of collagen fibers, and is found in areas such as the dermis of the skin and the capsules of organs.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}