Import Question JSON

Current Question (ID: 13756)

Question:

Select the incorrectly matched pair from the following:

Options:

1. Chondrocytes - Smooth muscle cells
2. Neurons - Nerve cells
3. Fibroblast - Areolar tissue
4. Osteocytes - Bone cells

Solution:

Chondrocytes are cells found in cartilage, which is a type of connective tissue that provides support and cushioning to joints and other structures in the body. Chondrocytes are responsible for producing and maintaining the extracellular matrix of cartilage. Smooth muscle cells, on the other hand, are a type of muscle cell that are found in the walls of internal organs, such as the intestines, bladder, and blood vessels. They are responsible for involuntary movements, such as peristalsis and vasoconstriction. Therefore, option 1 is the incorrectly matched pair. Options 2, 3, and 4 are correctly matched pairs. Neurons and nerve cells are different names for the same type of specialized cell that transmits electrical and chemical signals in the nervous system. Fibroblasts are cells found in areolar tissue and other types of connective tissue that produce and maintain the extracellular matrix. Osteocytes are cells found in bone tissue that help to maintain bone structure and regulate calcium metabolism.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}