Import Question JSON

Current Question (ID: 13799)

Question:
Intercalated disc are a type of
Options:
  • 1. Adherent junction.
  • 2. Desmosomes.
  • 3. Communicating junction.
  • 4. Tight junction.
Solution:
Intercalated discs are a type of communicating junction. Communicating junctions, also known as gap junctions, are specialized intercellular connections that allow direct communication between adjacent cells. Intercalated discs are specialized structures found in cardiac muscle cells that contain gap junctions and desmosomes. They help to synchronize the contraction of cardiac muscle cells, allowing the heart to function as a coordinated unit. Adherens junctions are another type of intercellular connection that help to hold cells together, typically through the use of cadherin proteins. Desmosomes are similar to adherens junctions but are stronger and more stable, often found in tissues that undergo a lot of mechanical stress. Tight junctions, on the other hand, are intercellular connections that prevent the movement of molecules between adjacent cells, helping to maintain the integrity of epithelial tissues.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}