Import Question JSON

Current Question (ID: 14149)

Question:

Muscularis layer of the wall of the alimentary canal is formed by:-

Options:

1. Smooth muscle arranged into an inner longitudinal and an outer circular layer
2. Smooth muscle arranged into an inner circular and an outer longitudinal layer
3. Skeletal muscle arranged into an inner longitudinal and an outer circular layer
4. Skeletal muscle arranged into an inner circular and an outer longitudinal layer

Solution:

The muscularis layer is responsible for the peristaltic movements that propel food through the digestive tract. The inner circular layer of smooth muscle fibers contracts to narrow the lumen of the alimentary canal, while the outer longitudinal layer of smooth muscle fibers contracts to shorten the length of the tube. Option 1, "Smooth muscle arranged into an inner longitudinal and an outer circular layer," is incorrect because the arrangement of the smooth muscle fibers is reversed. Option 3, "Skeletal muscle arranged into an inner longitudinal and an outer circular layer," is incorrect because skeletal muscle is not found in the muscularis layer of the alimentary canal, except in a few specialized regions such as the upper esophagus and external anal sphincter. Option 4, "Skeletal muscle arranged into an inner circular and an outer longitudinal layer," is also incorrect for the same reason.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}