Import Question JSON

Current Question (ID: 14325)

Question:
The maximum volume of air a person can breathe in after a forced expiration is
Options:
  • 1. (A) only
  • 2. (A) & (B) only
  • 3. (A), (B) & (C) only
  • 4. (A), (B), (C) & (D)
Solution:
The maximum volume of air a person can breathe in after a forced expiration is known as inspiratory capacity (IC), which is the sum of tidal volume (TV) and inspiratory reserve volume (IRV): IC = TV + IRV. Vital capacity (VC) is the maximum volume of air a person can exhale after a maximal inhalation, and is equal to the sum of tidal volume, inspiratory reserve volume, and expiratory reserve volume (ERV): VC = TV + IRV + ERV. Total lung capacity (TLC) is the maximum volume of air the lungs can hold after a maximal inhalation, and is equal to the sum of all four lung volumes: TLC = TV + IRV + ERV + residual volume (RV).

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}