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Current Question (ID: 14363)

Question:

At 40 mmHg of partial pressure of oxygen haemoglobin is _____ saturated

Options:

1. 50 %
2. 75 %
3. 85 %
4. 35 %

Solution:

At 40 mmHg of partial pressure of oxygen, haemoglobin is approximately 75% saturated. This means that out of the total haemoglobin molecules present, 75% have oxygen bound to them. The oxygen saturation of haemoglobin is dependent on the partial pressure of oxygen (PO₂) in the surrounding environment. The relationship between PO₂ and haemoglobin saturation is described by the oxygen dissociation curve. At lower PO₂ levels, such as 40 mmHg, haemoglobin is not fully saturated with oxygen, but still has a relatively high saturation of around 75%. As the PO₂ increases, the saturation of haemoglobin with oxygen also increases, until it reaches a maximum saturation of 100% at very high PO₂ levels.

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}