Import Question JSON

Current Question (ID: 14371)

Question:

Consider the characters of a respiratory control center in humans: I. It is located in pons II. It moderates the functions of respiratory rhythm center III. Its absence results in an increase in depth of respiration The respiratory control center is:

Options:

1. Pneumotaxic center
2. Apneustic center
3. Chemosensitive zone
4. Dorsal group

Solution:

The pneumotaxic center is located in the pons and it moderates the functions of respiratory rhythm center. It is responsible for fine-tuning the breathing pattern by regulating the depth and rate of respiration. Its absence results in an increase in the depth of respiration. The apneustic center is another respiratory center located in the pons that regulates the inspiratory phase of respiration, and its absence results in a decrease in the depth of respiration. The chemosensitive zone is a region of the brainstem that detects changes in the levels of oxygen, carbon dioxide, and pH in the blood and regulates breathing accordingly. The dorsal group is a group of neurons located in the medulla oblongata that is involved in the regulation of the basic rhythm of respiration.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}