Import Question JSON

Current Question (ID: 14392)

Question:

Which of the following options correctly represents the lung conditions in asthma and emphysema, respectively?

Options:

1. Inflammation of bronchioles; decreased respiratory surface
2. Increased number of bronchioles; increased respiratory surface
3. Increased respiratory surface; inflammation of bronchioles
4. Decreased respiratory surface; inflammation of bronchioles

Solution:

Asthma is caused due to an allergic reaction to foreign substances that affect the respiratory tract. Its symptoms are- Spasm of smooth muscles present in walls of the bronchiole. Coughing, Wheezing (means producing sound during breathing). Difficulty in breathing due to inflammation, i.e., swelling and redness of bronchi and bronchioles. Emphysema is a chronic disorder which is caused by excessive cigarette smoking. Its symptoms are- The walls of alveoli are damaged due to excessive smoking, loss of elasticity of walls of bronchioles and alveoli. Surface area for exchange of gases is reduced. Alveolar sacs remain filled with air even after expiration. The lungs remain inflated as exhalation becomes difficult.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}