Import Question JSON

Current Question (ID: 14398)

Question:
The binding of Hb with Carbon dioxide forms
Options:
  • 1. Methamoglobin
  • 2. Carbamino-haemoglobin
  • 3. Oxyhaemoglobin
  • 4. none of these
Solution:
When carbon dioxide (CO₂) enters the blood, it reacts with water (H₂O) to form carbonic acid (H₂CO₃), which then dissociates into bicarbonate ions (HCO₃⁻) and hydrogen ions (H⁺). The hydrogen ions bind to haemoglobin (Hb) to form deoxyhaemoglobin and the bicarbonate ions diffuse out of the red blood cells (RBCs) into the plasma in exchange for chloride ions (Cl⁻) via the chloride shift. Additionally, carbon dioxide directly binds to amino groups of the globin protein of haemoglobin to form carbamino-haemoglobin (HbCO₂), which accounts for approximately 20-30% of the carbon dioxide transported in the blood. The formation of carbamino-haemoglobin does not interfere with the oxygen-carrying capacity of Hb.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}