Import Question JSON

Current Question (ID: 14435)

Question:
Person with blood group AB is considered as universal recipient because he has
Options:
  • 1. Both A and B antigens on RBC but no antibodies in the plasma
  • 2. Both A and B antibodies in the plasma
  • 3. No antigen on RBC and antibody in the plasma
  • 4. Both A and B antigens in the plasma but no antibodies.
Solution:
Blood group AB is universal recipient because the person with AB blood group has both A and B antigens on RBC but no antibodies in the plasma. Other blood group and their genotypes are: Blood Group A: Antigen-A on RBC, Anti-b in serum, Genotypes AA/AO. Blood Group B: Antigen-B on RBC, Anti-a in serum, Genotypes BB/BO. Blood Group O: None on RBC, Anti a and b in serum, Genotype O.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}