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Current Question (ID: 14461)

Question:

Match the following nodal tissues of heart with their correct location Column I (a) AV node (b) SA node (c) Bundle branch (d) Purkinje fibres Column II (i) Right upper corner of the right atrium (ii) Left upper corner of the right atrium (iii) Base of inter atrial septum tilted towards right (iv) Lower right corner of the right atrium (v) Interventricular septum (vi) Musculature of ventricles

Options:

1. (iii) (ii) (vi) (v)
2. (iii) (i) (v) (vi)
3. (i) (iii) (v) (vi)
4. (v) (iv) (vi) (iii)

Solution:

Page 284, XI NCERT

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}