Import Question JSON

Current Question (ID: 14503)

Question:

The value of beat volume is

Options:

1. 5L
2. 70 mL
3. 140 mL
4. 90 mL

Solution:

The beat volume, also known as stroke volume, refers to the amount of blood that is ejected from the left ventricle of the heart with each heartbeat. In a healthy adult, the average stroke volume at rest is around 70 mL per beat. The cardiac output, which is the volume of blood pumped out by the heart in one minute, is calculated by multiplying the stroke volume by the heart rate. For example, if the stroke volume is 70 mL and the heart rate is 70 beats per minute, the cardiac output would be 4.9 L per minute (70 mL x 70 beats/min = 4,900 mL/min or 4.9 L/min). Option (1) 5L is incorrect as it is the average blood volume in an adult human body and not the stroke volume. Option (3) 140 mL is also incorrect as it is higher than the normal range of stroke volume and it can be seen in some pathological conditions. Option (4) 90 mL is also incorrect as it is higher than the normal range of stroke volume.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}