Import Question JSON

Current Question (ID: 14609)

Question:

Glomerulus along with Bowman's Capsule is called as

Options:

1. Malpighian body
2. Renal capsule
3. Renal column
4. Malpighian Tubule

Solution:

Glomerulus along with Bowman's capsule is called as the Malpighian body. The Malpighian body is the functional unit of the kidney that is involved in the process of filtration of blood and formation of urine. The glomerulus is a network of capillaries surrounded by Bowman's capsule, which is a double-walled epithelial cup-like structure. The blood is filtered through the glomerulus and the filtered fluid passes into Bowman's capsule. This filtered fluid is known as the glomerular filtrate and it contains water, electrolytes, glucose, and other small molecules. The filtrate then passes through the tubules where reabsorption and secretion take place to form urine. The renal capsule is a layer of connective tissue that surrounds the kidney and protects it from injury. The renal column is a part of the cortex of the kidney that extends into the medulla, dividing the medulla into pyramids. The Malpighian tubule is a tubular structure found in insects that functions as the excretory system.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}