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Current Question (ID: 14644)

Question:
Which of the following part of the nephron is not involved in tubular secretion?
Options:
  • 1. Bowman's capsule
  • 2. PCT
  • 3. DCT
  • 4. Collecting Duct
Solution:
Tubular secretion is the process by which substances are actively transported from the blood into the tubules for excretion in the urine. This process occurs primarily in the proximal convoluted tubule (PCT), the distal convoluted tubule (DCT), and the collecting duct. Bowman's capsule is the initial part of the nephron that surrounds the glomerulus and collects the filtrate that is produced by glomerular filtration. Bowman's capsule is not directly involved in the process of tubular secretion. In contrast, the PCT plays a major role in tubular secretion, as it actively transports substances such as hydrogen ions, organic acids, and bases from the blood into the tubules. The DCT and the collecting duct also participate in tubular secretion, primarily by transporting ions such as potassium and hydrogen ions into the tubules for excretion in the urine.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}