Import Question JSON

Current Question (ID: 14665)

Question:

An increase in the blood flow to the atria of the heart can cause the release of:

Options:

1. Erythropoietin
2. Atrial natriuretic factor
3. Renin
4. Aldosterone

Solution:

An increase in blood flow to the atria of the heart can stimulate the release of a hormone called atrial natriuretic peptide (ANP) or atrial natriuretic factor (ANF). ANF is released by specialized cells in the atria of the heart in response to increased stretching of the atrial walls due to increased blood volume or pressure. ANF acts to regulate fluid and electrolyte balance in the body. It promotes the excretion of sodium and water by the kidneys, leading to increased urine production and a reduction in blood volume and blood pressure. Option (1) - Erythropoietin is a hormone produced by the kidneys in response to low oxygen levels in the blood. It stimulates the production of red blood cells in the bone marrow. Option (3) - Renin is an enzyme produced and released by specialized cells in the kidneys in response to low blood pressure or low blood volume. It initiates the renin-angiotensin-aldosterone system (RAAS), which helps regulate blood pressure and fluid balance. Option (4) - Aldosterone is a hormone produced by the adrenal glands. It acts on the kidneys to promote the reabsorption of sodium and the excretion of potassium, thereby regulating fluid and electrolyte balance.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}