Import Question JSON

Current Question (ID: 14675)

Question:

This hormone promotes loss of sodium and water in urine, thereby increasing urinary output. This hormone is released from

Options:

1. JG cells
2. Liver
3. Medulla
4. Atrial walls of heart

Solution:

The hormone that promotes loss of sodium and water in urine, thereby increasing urinary output, is called atrial natriuretic peptide (ANP). ANP is released from the atrial walls of the heart in response to an increase in blood volume or pressure. ANP acts on the kidneys to increase sodium and water excretion, which helps to reduce blood volume and pressure. Option 1 (JG cells) is incorrect because JG (juxtaglomerular) cells in the kidney release renin, not ANP. Renin is involved in regulating blood pressure and the production of the hormone aldosterone. Option 2 (liver) is incorrect because the liver does not release ANP. The liver is involved in the production of many different hormones, enzymes, and other substances, but not ANP. Option 3 (medulla) is incorrect because the medulla of the kidney is involved in the production of urine and the regulation of fluid and electrolyte balance, but it does not release ANP.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}