Import Question JSON

Current Question (ID: 14681)

Question:

For the ejection of urine the voluntary signal is given by

Options:

1. ANS
2. CNS
3. PNS
4. Afferent arterioles

Solution:

The voluntary signal for the ejection of urine is given by the Central Nervous System (CNS). The CNS consists of the brain and spinal cord and is responsible for coordinating and controlling various bodily functions, including voluntary actions. When it comes to urination, the CNS plays a role in initiating and controlling the voluntary aspect of the process. Specifically, the micturition reflex, which controls the release of urine, involves both involuntary and voluntary components. The involuntary part of the reflex is regulated by the Autonomic Nervous System (ANS), while the voluntary part is controlled by the CNS. When the bladder fills with urine and reaches a certain level of distension, sensory signals are sent to the CNS, which then sends motor signals back to the bladder and the external urethral sphincter. The CNS can override or initiate the voluntary relaxation of the external urethral sphincter, allowing for the voluntary control of urine release.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}