Import Question JSON

Current Question (ID: 14696)

Question:

The osmotic concentration of glomerular filtrate is the highest at the bottom of the U-shaped Henle's loop. It is about __________ mOsmL⁻¹

Options:

1. 300
2. 600
3. 900
4. 1200

Solution:

The osmotic concentration of glomerular filtrate varies along the length of the Henle's loop due to the countercurrent multiplier mechanism that concentrates the urine. The descending limb of the loop is permeable to water but not to ions, so water moves out of the filtrate by osmosis, leading to an increase in the osmotic concentration of the filtrate. In contrast, the ascending limb is impermeable to water but permeable to ions, so ions are actively transported out of the filtrate, leading to a decrease in the osmotic concentration of the filtrate. The maximum osmotic concentration of the filtrate occurs at the bottom of the loop of Henle in the renal medulla, where the osmotic concentration can reach up to 1200 mOsm/L.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}