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Current Question (ID: 14864)

Question:

In the given four statements (a-d), select the options, which includes all the correct ones only: (a) Fibula does not participate in knee joint formation. (b) Tarsal bones are much larger and stronger than carpal bones because they have to support and distribute body weight. (c) Scapula situated dorsally in thoracic region between 2nd and 7th rib. (d) Two half of the pelvis girdle meet dorsally to form the pubic symphysis containing fibrous cartilage.

Options:

1. Statement (a), (b), (c)
2. Statement (a), (c), (d)
3. Statement (b), (c), (d)
4. Statement (a), (b), (c), (d)

Solution:

Explanation Page 311, XI NCERT

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}