Import Question JSON

Current Question (ID: 15151)

Question:

Given ahead is an incomplete table about certain hormones, their source glands and one major effect of each on the body in humans. Identify the correct option for the three blanks A, B and C.

Options:

1. Placenta Insulin Vasopressin
2. Ovary Insulin Calcitonin
3. Placenta Glucagon Calcitonin
4. Ovary Glucagon Growth hormone

Solution:

Ovary is the primary female sex organ that produces the female gamete (ovum) and several steroid hormones (ovarian hormones). The two steroid hormones produced by ovary are oestrogen and progesterone. Oestrogens produce wide ranging actions such as stimulation of growth and activities of female secondary sex organs, development of growing ovarian follicles, appearance of female secondary sex characters (e.g., high pitch of voice, etc.) mammary gland development. Oestrogens also regulate female sexual behaviour. The pars distalis region of pituitary, commonly called produced anterior pituitary, Growth Hormone (GH), prolactin (PRL), Thyroid stimulating Hormone (ACTH), Luteinizing hormone (LH) and follicle stimulating hormone(FSH). Over secretion of GH stimulates abnormal growth of the body lead to gigantism and low secretion of GH results in stunted growth resulting in pituitary dwarfism. Alpha cells of islets of Langerhans of the endocrine pancreas secrete a hormone called glucagon. It is a peptide hormone and plays an important role in maintaining the normal blood glucose levels. It acts mainly on the liver cells (hepatocytes) and stimulates glycogenolysis resulting in an increased blood sugar (hyperglycemia). In addition, this hormone stimulates the process of gluconeogenesis which also contributes to hyperglycemia. Glucagon reduces the cellular glucose uptake and utilization. Thus, glucagon is a hyperglycemic hormone.

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}