Import Question JSON

Current Question (ID: 15470)

Question:

Suppose a man has 200 million sperms in an ejaculate and he is fertile. Opt a correct option.

Options:

1. 125 million sperm with normal shape and size
2. 30 million with vigorous motility
3. 40 million with vigorous motility
4. More than one option

Solution:

As per the criteria, at least 60% must be of normal shape and size. So, (1) has 125 million sperm with normal shape and size which is greater than, 120 million, 60% of 200 million. Also, the number of sperms with vigorous motility should be at least, 80 million, 40% of 200 million. Please note that the language in NCERT regarding the number of sperms with vigorous motility is confusing. The number of sperms with vigorous motility should at least be 40% of the count of total sperms and not 40% of the count of sperms with normal shape and size. NCERT Reference: PAGE 48, XII NCERT

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}