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Current Question (ID: 15786)

Question:
Correct order is [1991]
Options:
  • 1. Palaeozoic → Archaeozoic → Coenozoic
  • 2. Archaeozoic → Palaeozoic → Proterozoic
  • 3. Palaeozoic → Mesozoic → Coenozoic
  • 4. Mesozoic → Archaeozoic → Proterozoic
Solution:
Era is a division of geological time that includes one or more periods. It follows the order Palaeozoic, Mesozoic and Coenozoic. Palaeozoic and Mesozoic eras are sub-divided into periods but Coenozoic is divided into periods and epochs. Mesozoic era is the Age of reptiles, and Coenozoic era is called as 'Age of mammals and birds'.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}