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Current Question (ID: 16163)

Question:

Consider the following four statements (1-4) regarding kidney transplant and select the two correct ones out of these. (1) Even if a kidney transplant is proper the recipient may need to take immuno-suppressants for a long time (2) The cell-mediated immune response is responsible for the graft rejection (3) The B-lymphocytes are responsible for rejection of the graft (4) The acceptance of rejection of a kidney transplant depends on specific interferons The two correct statements are

Options:

1. (2) and (3)
2. (3) and (4)
3. (1) and (3)
4. (1) and (2)

Solution:

To prevent graft (kidney transplant) rejection, the principle is to use chemicals, which inhibit the entire activity of the immune system. When this occurs graft rejection is delayed. It has been shown that immunosuppression may make the patients more prone to develop cancers. One way of overcoming the problems of radiation and immunosuppression is to suppress only the cells responsible for rejection, normally the killer T-cells. In this way, the rest of the patients immune system would continue to function normally. The most promising approach is to treat the patient with monoclonal antibodies that recognize and destroy the killer T-cells. A monoclonal antibody has been developed, which is a very effective at preventing rejection of transplanted kidneys.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}