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Current Question (ID: 16379)

Question:
Arrange the following steps in order: 1) Restriction Digestion 2) Running Agarose gel 3) Elution of bands 4) Purification of DNA 5) ligation 6) transformation 7) Cloning
Options:
  • 1. 1-2-3-4-5-6-7
  • 2. 1-5-6-7-2-3-4
  • 3. 1-2-3-5-6-7-4
  • 4. 2-3-4-1-5-6-7
Solution:
NCERT page number 197-198 11.2 Tools of RDT 11.2.1 Restriction Enzymes Biotechnology: Principles And Processes

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}