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Current Question (ID: 16432)

Question:

$\text{The electric field at a point is:}$ $\text{(a) always continuous.}$ $\text{(b) continuous if there is no charge at that point.}$ $\text{(c) discontinuous only if there is a negative charge at that point.}$ $\text{(d) discontinuous if there is a charge at that point.}$ $\text{Choose the correct option:}$

Options:

1. $\text{(a), (b)}$
2. $\text{(b), (d)}$
3. $\text{(c), (d)}$
4. $\text{(a), (d)}$

Solution:

$\text{(2) Hint: The electric field lines originate from a positive charge and end at a negative charge.}$ $\text{The electric field due to a charge Q at a point in space may be defined as the force that a unit positive charge would experience if placed at that point.}$ $\text{Thus, the electric field due to the charge Q will be continuous, if there is no charge at that point.}$ $\text{It will be discontinuous if there is a charge at that point.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}