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Current Question (ID: 16454)

Question:

$\text{Which of the following graphs shows the variation of electric field } E \text{ due to a hollow spherical conductor of radius } R \text{ as a function of distance from the centre of the sphere?}$

Options:

1. $\text{Graph 1}$
2. $\text{Graph 2}$
3. $\text{Graph 3}$
4. $\text{Graph 4}$

Solution:

$\text{Hint: } E = \frac{Q}{4\pi\varepsilon_0 r^2}$ $\text{Explanation: The electric field due to a hollow spherical conductor is governed by the following equation;} E = 0, \text{ for } r < R \ldots (1)$ $\text{and, } E = \frac{Q}{4\pi\varepsilon_0 r^2} \text{ for } r \geq R \ldots (2)$ $\text{i.e. inside the conductor field will be zero and outside the conductor will vary according to } \Rightarrow E \propto \frac{1}{r^2}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}