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Current Question (ID: 16485)

Question:

$\text{If 50 J of work must be done to move an electric charge of 2 C from a point where the potential is } -10 \text{ volts to another point where the potential is V volts, then the value of V is:}$ $1.\ 5 \text{ volts}$ $2.\ -15 \text{ volts}$ $3.\ +15 \text{ volts}$ $4.\ +10 \text{ volts}$

Options:

1. $5 \text{ volts}$
2. $-15 \text{ volts}$
3. $+15 \text{ volts}$
4. $+10 \text{ volts}$

Solution:

$\text{Hint: } W = Q \Delta V$ $\text{Step: Find the value of the potential.}$ $\text{Given: } W = 50 \text{ J}, Q = 2 \text{ C}, V_1 = -10 \text{ V}$ $\text{The work done is given by:}$ $\Rightarrow W = Q \Delta V \Rightarrow 50 = 2 \left[V_2 - V_1\right]$ $\Rightarrow 50 = 2 \left[V_2 - (-10)\right] \Rightarrow V_2 = 15 \text{ V}$ $\text{Hence, option (3) is the correct answer.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}