Import Question JSON

Current Question (ID: 16491)

Question:
$\text{In the figure the charge } Q \text{ is at the centre of the circle. Work done by the conservative force is maximum when another charge is taken from point } P \text{ to:}$
Options:
  • 1. $K$
  • 2. $L$
  • 3. $M$
  • 4. $N$
Solution:
$\text{The points } P, L, M \text{ and } N \text{ lie at the equipotential surface as they are equidistant from the charge.}$ $\text{So, the work done in moving a charge from } P \text{ to } L, P \text{ to } M \text{ and } P \text{ to } N \text{ is zero due to no potential difference.}$ $\text{The potential difference between } P \text{ and } K \text{ is not equal to zero due to different distances.}$ $\text{So, the work done will be maximum in moving the charge from } P \text{ to } K.$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}