Import Question JSON

Current Question (ID: 16504)

Question:
$\text{The work done to move a charge along an equipotential from } A \text{ to } B:$
Options:
  • 1. $\text{can not be defined as } - \int_{A}^{B} \vec{E} \cdot \vec{dl}$
  • 2. $\text{must be defined as } - \int_{A}^{B} \vec{E} \cdot \vec{dl}$
  • 3. $\text{is zero}$
  • 4. $\text{can have a non-zero value.}$
Solution:
$\text{NEETprep Answer:}$ $\text{(3) Hint: The work done depends on the potential difference.}$ $\text{Step 1: Find the work done.}$ $\text{Work done in displacing a charged particle is given by:}$ $W_{12} = q(V_2 - V_1)$ $\text{Step 2: Find the potential difference.}$ $\text{The line integral of the electrical field from the point 1 to 2 gives potential difference.}$ $V_2 - V_1 = - \int_{1}^{2} E \cdot dl$ $\text{For equipotential surface, V2-V1 = 0 and W = 0}$ $\text{Note: If the displaced charged particle is + 1 C, then and only then, option (b) is correct. But the NCERT exemplar book has given (b) as the correct option which is probably not so under the given conditions.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}