Import Question JSON

Current Question (ID: 16532)

Question:

$\text{Which of the following statements is correct regarding the electrostatics of conductors?}$

Options:

1. $\text{The interior of the conductor with no cavity can have no excess charge in the static situation.}$
2. $\text{The electrostatic potential is constant throughout the volume of the conductor.}$
3. $\text{The electrostatic potential has the same value inside as that on its surface.}$
4. $\text{All of the above statements are correct.}$

Solution:

$\text{Hint: Recall the properties of the conductor.}$ $\text{Step: Analyse each statement one by one.}$ $\text{In electrostatics, any excess charge placed on a conductor resides on its surface.}$ $\text{The electric field inside a conductor is zero, meaning no charge can exist in the interior of the conductor in a static situation.}$ $\text{So, statement (1) is correct.}$ $\text{Since the electric field inside a conductor is zero in electrostatics, there is no potential difference between any two points inside the conductor.}$ $\text{Therefore, the potential must be constant throughout the volume of the conductor.}$ $\text{So, statement (2) is correct.}$ $\text{As the electric field inside the conductor is zero, the potential difference between the two points inside the conductor is zero.}$ $\text{Therefore, the potential at every point inside the conductor is the same.}$ $\text{The potential inside the conductor and on the surface of the conductor is given as,}$ $V_{\text{Inside}} = V_{\text{Surface}} = \frac{kQ}{R}$ $\text{So, statement (3) is correct.}$ $\text{Therefore, all the statements are correct.}$ $\text{Hence, option (4) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}