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Current Question (ID: 16582)

Question:
$\text{An air capacitor of capacity } C = 10 \, \mu\text{F is connected to a constant voltage battery of } 12 \, \text{V.}$ $\text{Now the space between the plates is filled with a liquid of dielectric constant } 5.$ $\text{The charge that flows now from battery to the capacitor is:}$
Options:
  • 1. $120 \, \mu\text{C}$
  • 2. $699 \, \mu\text{C}$
  • 3. $480 \, \mu\text{C}$
  • 4. $24 \, \mu\text{C}$
Solution:
$\Delta q = KCV - CV$ $= 5 \times 10^{-5} \times 12 - 10^{-5} \times 12$ $= 12 \times 10^{-5} \times 4 = 48 \times 10^{-5}$ $= 480 \, \mu\text{C}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}