Import Question JSON

Current Question (ID: 16644)

Question:
$\text{What is the reading of the voltmeter of resistance } 1200 \, \Omega \text{ connected in the following circuit diagram?}$
Options:
  • 1. $2.5 \, \text{V}$
  • 2. $5.0 \, \text{V}$
  • 3. $7.5 \, \text{V}$
  • 4. $40 \, \text{V}$
Solution:
$\text{Hint: Reading of voltmeter = voltage across the } 600 \, \Omega.$ $\text{Step 1: Calculate the equivalent resistance of voltmeter and } 600 \, \Omega.$ $R' = \frac{1200 \times 600}{1200 + 600} = 400 \, \Omega.$ $\text{Step 2: Find the voltage drop across } 400 \, \Omega$ $\text{As two resistances of } 400 \, \Omega \text{ are connected in series across a cell of } 10 \, \text{V}$ $\text{So, the voltage drop across each } 400 \, \Omega \text{ will be half of } 10 \, \text{V i.e., } 5 \, \text{V.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}